[Python] Write expression to pickup specific content from a column using pandas

I think I may be asking for the impossible. I am trying to pull the following from the Notes column and remove all words left over. The format I wish to grab is content that looks like '0-0-0' or '0 - 0 - 0'. But the expression I wrote is only grabbing row 5 & 6. I'll be eternally grateful.

import pandas as pd
import re as re

data = {'Notes': ['1,088 errors - 0 comments - 1109 pages', '76-0-143-SIS',
'0 - 18 - 624 *flashcard questions (119 pgs PDF)',
'0-0-1 page', '3 - 8 - 15 M1', '0 - 6 - 115', '35-0-100']}

QA_data = pd.DataFrame (data, columns = ['Notes'])

print (QA_data)


And it turns out to be like the following:

Notes
0 1,088 errors - 0 comments - 1109 pages
1 76-0-143-SIS
2 0 - 18 - 624 *flashcard questions (119 pgs PDF)
3 0-0-1 page
4 3 - 8 - 15 M1
5 0 - 6 - 115
6 35-0-100


I used regex to build my expressions and am using pandas to pull the necessary information from a string.

space = re.compile('^\d+ - \d+ - \d+$')
nospace = re.compile('^\d+-\d+-\d+$')
print(checker.match("123 -123 - 123"))


Used a for loop to match my strings and replace everything else with ''.

task_dicts = QA_data.to_dict()
#print(task_dicts.keys())
#print(task_dicts["Notes"])
for keys in task_dicts["Notes"]:
if not space.match(str(task_dicts["Notes"][keys])) and not space.match(str(task_dicts["Notes"][keys])):
task_dicts["Notes"][keys] = ''

for keys in task_dicts["Notes"]:
print(task_dicts["Notes"][keys])

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