[Python] Why doesn't exec() create objects in local/global scope?

I'm trying to find an IPython counterpart to Spyder's runfile. According to this page, "exec() will execute the input code in the current scope" by default. Therefore, I expect the following to create objects TestFunc and Doggy in the current scope:

# Script.py
#----------
def TestFunc():
printf("I am TestFunc.")
Doggy = "Doggy"


To "source" the code from the IPython REPL, I found the following function from this tutorial, which I paste into the REPL:

def execute_python_file_with_exec(file_path):
try:
with open(file_path, 'r') as file:
code = file.read()
exec(code)
except FileNotFoundError:
print(f"Error: The file '{file_path}' does not exist.")
except Exception as e:
print(f"An error occurred: {e}")


I then use it to run Script.py and query the local and global namespace:

execute_python_file_with_exec('Script.py')

print("Locals:")
for item in dir():
print( item, end=", " )

print("Globals:")
for item in globals():
print( item, end=", " )


Neither of the namespaces contain TestFunc or Doggy.

Locals:
In, Out, _, _2, _5, _6, __, ___, __builtin__,
__builtins__, __doc__, __loader__, __name__,
__package__, __spec__, _dh, _i, _i1, _i2, _i3,
_i4, _i5, _i6, _i7, _i8, _ih, _ii, _iii, _oh,
execute_python_file_with_exec, exit,
get_ipython, item, open,

Globals:
__name__, __doc__, __package__, __loader__,
__spec__, __builtin__, __builtins__, _ih, _oh,
_dh, In, Out, get_ipython, exit, quit, open,
_, __, ___, _i, _ii, _iii, _i1,
execute_python_file_with_exec, _i2, _2, _i3,
_i4, _i5, _5, _i6, _6, _i7, item, _i8, _i9, In
[10]:


What am I misunderstanding about exec()?

I am using IPython version 8.15.0 from Anaconda.

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