[Python] Why does groupby().apply() produce inconsistent results on identical groups when the...

Discussão em 'Python' iniciado por Stack, Novembro 26, 2025.

  1. Stack

    Stack Membro Participativo

    I noticed that groupby().apply() produces different results for two groups that look identical, except that the overall DataFrame has duplicate index values.

    Here is a minimal reproducible example:

    import pandas as pd

    df = pd.DataFrame({
    'group': ['A','A','B','B','B'],
    'value': [1,2,1,2,2]
    }, index=[0,1,1,2,3]) # note the duplicate index: 1 appears twice

    result = df.groupby('group').apply(lambda g: g)
    print(result)


    Output:

    group value
    group
    A A 1
    A 2
    B B 1
    B 2
    B 2


    But when I reset the index so it becomes unique:

    df2 = df.reset_index(drop=True)
    print(df2.groupby('group').apply(lambda g: g))


    I get a different structure (especially inside the B group).

    Why does the presence of duplicate index values change how groupby().apply() constructs the returned index?What is the correct way to preserve the original rows and avoid unexpected index nesting when applying functions?

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