[Python] Why am I getting an "execv(file, args)" error when using execl()?

I am trying to use execl() to execute a new program but it keeps returning an execv() error saying that arg2 must not be empty.

if pid == 0:
print("This is a child process")
print("Using exec to another program")
os.execl("example_prg_02.py")


Why would this be the case when using execl()? Does execl() require args too?

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