[Python] Why am I getting an additional " at the very end of the sbrun string?

I am building a remote terminal with Python subprocess. Trying to capture the output and errors from subprocess.run().

Consider a variable cmd that contains "echo helloworld". If I print it right before the code below, it doesn't change, i.e. it contains the same "echo helloworld".

result = subprocess.run(f"cmd /c {cmd}", shell=True, capture_output=True, text=True)


The problem is, what I receive in the output is helloworld"; there is a double quote at the end of the string that can't be printed.

Full function code:

def runcmd(cmd:str) -> None:
try:
# cmd = cmd[:-1] didnt worked. i tried to remove the last " . even .replace() didnt worked
try:
# added a \" because it works with most commands. kind of a temp fix
result = sbrun(f"cmd /c \"{cmd}", shell=True, capture_output=True, text=True)
stdout = result.stdout
stderr = result.stderr
exit_code = result.returncode
except Exception as e:
stdout = ""
stderr = str(e)
exit_code = -1
if not stderr:stderr="none"
if not stdout:stdout="none"
output = f"OUTPUT:\t{stdout}\nERROR:\t{stderr}\nCODE:\t{exit_code}"
alsr = post(url+"terminal",json={"output"utput})
if alsr.status_code == 200:
log(f"{cmd} executed") # my remote logging function incase it goes bad
output = f"OUTPUT:\t{stdout}\nERROR:\t{stderr}\nCODE:\t{exit_code}"
alsr = post(url+"terminal",json={"output"utput})# the func to send the output to me
if not alsr.status_code == 200:
log(f"failed to send the output. The output was\t\t OUTPUT:\t{stdout}\nERROR:\t{stderr}\nCODE:\t{exit_code}")

except Exception as e:
log(f"runcmd thread error:\t{e}",state="WARN")


Why is that ghost quote there that can't be seen by any means?

Continue reading...