I understand that self is implicitly passed as an argument to methods when they are called. I am learning about descriptors and understand how functions "become" methods, I understand (at least conceptually) that attributes are "bound" to objects, I have read multiple articles online and Raymond Hettinger's Descriptor how to. In the example below, though, I just don't understand where the reference to the instance of the Function f (i.e. the parameter self on __get__, for which an argument will be implicitly passed) comes from. I contrast this with the self parameter on f itself, which I understand will get passed as an argument to parameter obj on __get__ when __get__ is called. How does Python know, when __get__ is called, what underlying function needs to be passed to MethodType? I know this is the argument which is passed to self, but how/when does this happen? I thought I understood how self worked when I learned about __get__, and how the __get__ on the function Type can either return a Function or a MethodType. class Function: def __get__(self, obj, objtype=None): "Simulate func_descr_get() in Objects/funcobject.c" if obj is None: return self return MethodType(self, obj) class D: def f(self, x): return x Continue reading...
