[Python] ValueError: min() arg is an empty sequence using bash orders

I am using a .sh bash orders file with the following calls to slurm jobs

for i in {0..705..13}
do
run -t 200:00 -c 1 -m 270 python3 code.py $i $((i + 13))
sleep 0.1
done


The file code.py, after importing libraries, contains

l_random_portions = np.arange(1000, 1800000000+2.5*10**6, 2.5*10**6)[int(sys.argv[1]):int(sys.argv[2])]
print(f'\nRandom portions from {min(l_random_portions)} to {max(l_random_portions)} tokens will be selected')


Strangely enough, some jobs give the following error just in the moment they start running

Traceback (most recent call last):
File "code.py", line n, in <module>
print(f'\nRandom portions from {min(l_random_portions)} to {max(l_random_portions)} tokens will be selected')
ValueError: min() arg is an empty sequence
srun: error: slurm21: task 0: Exited with exit code 1


I can't understand. If I define the vector and iterate over its elements manually I cannot find a way of creating an empty vector so that I reproduce the error. Where can it come from?

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