Given a date, add time interval (X years, X months, X weeks), return date: input args: input_time (datetime.date), interval (datetime.timedelta) return: datetime.date I looked at the datetime and datetime.timedelta docs class datetime.timedelta(days=0, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=0, weeks=0)¶. These works if I want to add a certain number of hours or weeks. However, I am trying to implement an operation such as date + 1 year: start = datetime.datetime(2000, 1, 1) # expected output: datetime.datetime(2001, 1, 1) # with the weeks, etc arguments given in timedelta, this fails unsurprisingly e.g start + datetime.timedelta(weeks = 52) # returns datetime.datetime(2000, 12, 30, 0, 0) Is this year-based operation possible with the basic tools of datetime - if so, how? For the year example, I could just do start.replace(year = 2001), but that approach will fail if I have months or weeks as input. The dateutil library seems more advanced, but I was not clear how well it interacts with the in-built datetime objects. I reviewed this similar question. Running Python 3.6.5 on MacOs. Continue reading...
