[Python] TypeError: request() got an unexpected keyword argument 'header' - when i use...

Discussão em 'Python' iniciado por Stack, Agosto 17, 2025.

  1. Stack

    Stack Membro Participativo

    i am trying scrape information from this website but keep getting status code: 403, So tried using header but got TypeError: request() got an unexpected keyword argument 'header'

    Code:

    import requests

    head = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:71.0) Gecko/20100101 Firefox/71.0'}
    url = "https://www.accuweather.com/en/bd/dhaka/28143/current-weather/28143"
    pageObj = requests.get(url, header = head)
    print("Status code: " + str(pageObj.status_code)) # *for testing purpose*


    Error:

    Traceback (most recent call last):
    File "F:/Python/PyCharm Community Edition 2019.2.3/Workshop/WEB_SCRAPING/test2.py", line 6, in <module>
    pageObj = requests.get(url, header = head)
    File "F:\Python\PyCharm Community Edition 2019.2.3\Workshop\WEB_SCRAPING\venv\lib\site-packages\requests\api.py", line 75, in get
    return request('get', url, params=params, **kwargs)
    File "F:\Python\PyCharm Community Edition 2019.2.3\Workshop\WEB_SCRAPING\venv\lib\site-packages\requests\api.py", line 60, in request
    return session.request(method=method, url=url, **kwargs)
    TypeError: request() got an unexpected keyword argument 'header'


    header from firefox dev tool

    what am i doing wrong?

    Continue reading...

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