[Python] TypeError on CodeType creation in Python 3

I'm trying to create a new CodeType, the following code runs just fine in Python 2.7, but in Python 3.2 I get an error:

def newCode(co_argcount = 0, co_nlocals = 0, co_stacksize = 0, co_flags = 0x0000,
co_code = bytes(), co_consts = (), co_names = (), co_varnames = (),
filename = "<string>", name = "", firstlineno = 0, co_lnotab = bytes(),
co_freevars = (), co_cellvars = ()):
"""wrapper for CodeType so that we can remember the synatax"""
print(type(co_stacksize))
return types.CodeType(co_argcount, co_nlocals, co_stacksize,
co_flags, co_code, co_consts, co_names, co_varnames,
filename, name, firstlineno, co_lnotab, co_freevars, co_cellvars)


Usage:

return newCode(co_code = code, co_stacksize = size, co_consts = consts)


The debug line proves that I'm sending in an int as co_stacksize...what changed in Python 3 to make this not work?

Edit: Here's the error (don't know why I forgot that before):

TypeError: an integer is required

Continue reading...