[Python] StratifiedKFold vs KFold in scikit-learn

Discussão em 'Python' iniciado por Stack, Fevereiro 1, 2025.

  1. Stack

    Stack Membro Participativo

    I use this code to test KFold and StratifiedKFold.

    import numpy as np
    from sklearn.model_selection import KFold,StratifiedKFold

    X = np.array([
    [1,2,3,4],
    [11,12,13,14],
    [21,22,23,24],
    [31,32,33,34],
    [41,42,43,44],
    [51,52,53,54],
    [61,62,63,64],
    [71,72,73,74]
    ])

    y = np.array([0,0,0,0,1,1,1,1])

    sfolder = StratifiedKFold(n_splits=4,random_state=0,shuffle=False)
    floder = KFold(n_splits=4,random_state=0,shuffle=False)

    for train, test in sfolder.split(X,y):
    print('Train: %s | test: %s' % (train, test))
    print("StratifiedKFold done")

    for train, test in floder.split(X,y):
    print('Train: %s | test: %s' % (train, test))
    print("KFold done")


    I found that StratifiedKFold can keep the proportion of labels, but KFold can't.

    Train: [1 2 3 5 6 7] | test: [0 4]
    Train: [0 2 3 4 6 7] | test: [1 5]
    Train: [0 1 3 4 5 7] | test: [2 6]
    Train: [0 1 2 4 5 6] | test: [3 7]
    StratifiedKFold done
    Train: [2 3 4 5 6 7] | test: [0 1]
    Train: [0 1 4 5 6 7] | test: [2 3]
    Train: [0 1 2 3 6 7] | test: [4 5]
    Train: [0 1 2 3 4 5] | test: [6 7]
    KFold done


    It seems that StratifiedKFold is better, so should KFold not be used?

    When to use KFold instead of StratifiedKFold?

    Continue reading...

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