[Python] Splitting string into two parts with digits occurring in both parts

I have a sample string like 3425%4368, % in the string devide it into two parts, I want to find all digitals in the first part that has occurrence in the second part.

you can see, 3 and 4 in the first part can also be found in second part.

re.findall(r'(\d).*%.*\1', '3425%4368')


is my code.

it only returns 3. I can not figure out why the script does not match 4, thanks!

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