The question is: Determine the number of natural six-digit numbers that do not contain the number 4 in their record, which can be represented as the sum of an odd number dividing by 109 without remainder, and the natural power of the number 3 Answers: 1)23124 2)24712 3)25902 4)26444 I keep getting 22138. Maybe the answers are not correct? count = 0 for a in range(109, 999999, 109): if a % 2 == 0: continue b = 1 while True: n = a + (3**b) if n > 999999: break if n >= 100000 and (str(n).count('4')<1): count += 1 b += 1 print(count) Continue reading...
