I have an issue with updating a python model that represents a table in snowflake using sqlalchemy. One of the columns is a variant field and when I attempt to update the model and save it back to the database snowflake complains that the value is not a variant. I've tried passing in the data as a dictionary as well as a json string, neither works. The model property is defined as: data = db.Column(snowsql.VARIANT) snowsql being an alias for the snowflake-sqlalchemy package, which is installed but it appears to only provide type dialects and not much else. Does anyone have any experience doing this? Update: The data that I am adding is a python list of dictionaries: new_data['data'] = [{'component': None, 'display_name': 'blah', 'key': None, 'row': {'display_name': 'blah', 'type': 'blah'}, 'sub_type': None, 'type': 'blah'}] Doing a json.dumps when setting the variant property: new_blah = Blah( data = json.dumps(new_data['data']) ) Results in: Expression type does not match column data type, expecting VARIANT but got VARCHAR(8905) for column DATA The json produced by the dumps: "[{\"component\":null,\"display_name\":\"blah\",\"key\":null,\"row\":{\"display_name\":\"blah\",\"type\":\"blah\"},\"sub_type\":null,\"type\":\"blah\"}]" Alternatively, attempting to assign the list without doing a json.dumps: sqlalchemy.exc.ProgrammingError: (snowflake.connector.errors.ProgrammingError) 252004: None: Failed processing pyformat-parameters; 'dict' object has no attribute 'replace' Continue reading...