Hello there fellow developers, The following is a question from a Python's studying list. The question asks to choose between 5 answers about which would be the output of print(v, m, n). a) [1, 2, 3], [2, 4, 6], [3, 6, 9] b) [3, 6, 9], [3, 6, 9], [3, 6, 9] c) [1, 2, 3], [1, 2, 3], [3, 6, 9] d) [1, 2, 3], [1, 2, 3], [2, 4, 6] e) [3, 6, 9], [1, 2, 3], [3, 6, 9] From my beginner perspective, v = [1, 2, 3] and m after running f1(v) should be m = [1, 2, 3] as well (and on debug I see m as [1, 2, 3] before hitting the n = f2(v) line). Then n should be [3, 6, 9] after running f2(v)(because of m *= 3). I know the right answer is B, I just cannot figure out why. Although wrong, my thinking process point to [1, 2, 3][1, 2, 3][3, 6, 9] as the answer. def f1(v): for elem in v: elem *= 2 return v def f2(m): for i in range(len(m)): m *= 3 return m v = [1,2,3] m = f1(v) n = f2(v) print(v, m, n) Please help me figure out why the output of this Python code is [3, 6, 9] [3, 6, 9] [3, 6, 9] instead of [1, 2, 3] [1, 2, 3] [3, 6, 9] Thanks. Continue reading...
