[Python] Run Python script as a windows service failed

I'm trying to create and run a Windows service from Python code.

from datetime import datetime
import win32serviceutil
import win32service
import win32event
import servicemanager
import socket

class Pythonservice(win32serviceutil.ServiceFramework):
_svc_name_ = 'MyWindowsService2'
_svc_display_name_ = 'MyWindowsService2'
_svc_description_ = 'Friendly Service'

def __init__(self, args):
win32serviceutil.ServiceFramework.__init__(self, args)
self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
self.isrunning = False

def SvcStop(self):
self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
self.isrunning = False
win32event.SetEvent(self.hWaitStop)

def SvcDoRun(self):
self.ReportServiceStatus(win32service.SERVICE_START_PENDING)
self.isrunning = True
self.ReportServiceStatus(win32service.SERVICE_RUNNING)
servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,
servicemanager.PYS_SERVICE_STARTED,
(self._svc_name_, ''))
self.main()

def main(self):
path = r"C:\Users\Documents\Projects\services\dist\Log.txt"
while self.isrunning:
rc = win32event.WaitForSingleObject(self.hWaitStop, 1000)
if rc == win32event.WAIT_OBJECT_0:
break
try:
with open(path, "w") as file:
now = datetime.now().strftime("%B %d, %y %H:%M:%S")
file.write(now)
except Exception as e:
servicemanager.LogMsg(servicemanager.EVENTLOG_ERROR_TYPE,
servicemanager.PYS_SERVICE_STARTED,
(f"Error: {str(e)}", ''))

if __name__ == '__main__':
win32serviceutil.HandleCommandLine(Pythonservice)


After that, I use pyinstaller to bundle it into an exe file:

pyinstaller --onefile --hidden-import=win32timezone --hidden-import=pywintypes win_service2.py

Then I successfully register the service:

sc create MyWindowsService2 binPath="C:\Users\Documents\Projects\services\dist\win_service2.exe"

Next, when I try to start it using the command: sc start MyWindowsService2

I get the error:

[SC] StartService FAILED 1053: The service did not respond to the start or control request in a timely fashion.
​

I tried to execute the following after creating the service: .\dist\win_service2.exe start and python .\win_service2.py start

but error:

Starting service MyWindowsService2 Error starting service: The service did not respond to the request in a timely manner.
​

I also tried registering the service using: sc create PythonApp binPath= "C:\Python\Python313\Python.exe --C:\Users\Documents\Projects\services\win_service2.py"

But I got the same error.

Please note that registration via nssm is not suitable!

Question: Why does this error occur?

Thanks a lot!

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