[Python] Rolling 2 dice in Python and if they are the same number, roll again, and continuing

Discussão em 'Python' iniciado por Stack, Maio 21, 2025.

  1. Stack

    Stack Membro Participativo

    So I need to write a Python program where I need to roll 2 dice and print the sum of the 2 dice. I got this so far:

    import random
    def monopoly():
    x = random.randrange(1,7)
    y = random.randrange(1,7)
    while True:
    if x != y:
    print(x, '+', y, '=', x+y)
    break


    Now, every time the 2 dice numbers are the same (2 + 2 or 3 + 3 etc.) You can throw again. If 3 times in a row the dice are the same, you need to go to jail. I thought I had to work with a while loop using continue like this:

    else:
    if x == y:
    print(x + y)
    continue
    #continuation of the code above


    Now if I do have an outcome where the dice are the same it keeps printing out the sum over and over again until I stop the program myself. But I don't know why.

    How do I fix This?, because I have no idea how to do this.

    Continue reading...

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