[Python] Return File/Streaming response from online video URL in FastAPI

I am using FastAPI to return a video response from googlevideo.com. This is the code I am using:

@app.get(params.api_video_route)
async def get_api_video(url=None):

def iter():
req = urllib.request.Request(url)

with urllib.request.urlopen(req) as resp:
yield from io.BytesIO(resp.read())


return StreamingResponse(iter(), media_type="video/mp4")


but this is not working

I want this Nodejs to be converted into Python FastAPI:

app.get("/download-video", function(req, res) {
http.get(decodeURIComponent(req.query.url), function(response) {
res.setHeader("Content-Length", response.headers["content-length"]);
if (response.statusCode >= 400)
res.status(500).send("Error");
response.on("data", function(chunk) { res.write(chunk); });
response.on("end", function() { res.end(); }); }); });

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