I have the following sentence: "The size of the lunch box is around 1.5l or 1500ml" How can I change this to: "The size of the lunch box is around 1.5 liter or 1500 milliliter" In some cases, the value might also be present as "1.5 l or 1500 ml" with a space. I am not be able to capture the "l" or "ml" when I am trying to build a function, or it is giving me an escape error. I tried: def stnd(text): text = re.sub('^l%',' liter', text) text = re.sub('^ml%',' milliliter', text) text = re.sub('^\d+\.\d+\s*l$','^\d+\.\d+\s*liter$', text) text = re.sub('^^\d+\.\d+\s*ml$%','^\d+\.\d+\s*milliliter$', text) return text Continue reading...
