I want to emulate this function. I want to round a floating point number down to the nearest multiple of 0.05 (or generally to the nearest multiple of anything). I want this: >>> round_nearest(1.29, 0.05) 1.25 >>> round_nearest(1.30, 0.05) 1.30 I can do this: import math def round_nearest(n, r): return n - math.fmod(n, r) >>> round_nearest(1.27, 0.05) 1.25 # Correct! >>> round_nearest(1.30, 0.05) 1.25 # Incorrect! Correct would be 1.30. The incorrect answer above is presumably due to floating point rounding. I could put some special case check to see if the n is "close enough" to a multiple of r and not do the subtraction, and that would probably work, but is there a better way? Or is this strategy the best option? Continue reading...
