Is there anyway to remove an item from a list in such a way that I return a new list without the removed element? For instance, if I have a list ['a','b','c','d','e'] (called my_list), then I would like a method that does the following my_list.newRemove('a') = ['b','c','d','e']. I want to do this in such a way that I could send the element to be removed and the new list as parameters of a function: func(element, my_list.newRemove(element)) for example: func('a', list.newRemove('a')) which would pass 'a' AND ['b','c','d','e'] I know I can do this by just passing the element and the entire list to the function, and then creating a new subList in the function without the passed element. However, I feel like it would look better to do it the way I'm asking. Is this just a fundamentally un-pythonic way of doing this? I learned to program with functional languages, and old habits die hard. Edit: mistakenly wrote set rather than list Edit 2: Here is an example of what I ultimately want to do: myList = ['a','b','c','d'] for element in myList: function(element, myList.newRemove(element) Where function does a calculation between the element and the rest of the elements in the list. Continue reading...
