[Python] Python: pick appropriate datatype size (int) automatically

Discussão em 'Python' iniciado por Stack, Março 19, 2025.

  1. Stack

    Stack Membro Participativo

    I'm allocating a (possibly large) matrix of zeros with Python and numpy. I plan to put unsigned integers from 1 to N in it.

    N is quite variable: could easily range from 1 all the way up to a million, perhaps even more.

    I know N prior to matrix initialisation. How can I choose the data type of my matrix such that I know it can hold (unsigned) integers of size N?

    Furthermore, I want to pick the smallest such data type that will do.

    For example, if N was 1000, I'd pick np.dtype('uint16'). If N is 240, uint16 would work, but uint8 would also work and is the smallest data type I can use to hold the numbers.

    This is how I initialise the array. I'm looking for the SOMETHING_DEPENDING_ON_N:

    import numpy as np
    # N is known by some other calculation.
    lbls = np.zeros( (10,20), dtype=np.dtype( SOMETHING_DEPENDING_ON_N ) )


    cheers!

    Aha!


    Just realised numpy v1.6.0+ has np.min_scalar_type, documentation. D'oh! (although the answers are still useful because I don't have 1.6.0).

    Continue reading...

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