[Python] Python - If statements in optional parameters

I have a prewritten piece of code that says:

setprecision = 0
printit(100.123, precision=6 if setprecision is None else setprecision)


My goal is to write a function that can handle all of these given parameters:

def printit(*text, precision=2):
printme = ''
for arg in text:
if (type(arg) is float) or (type(arg) is int):
printme += str(f"{arg:.{precision}f}")
else:
printme += arg
print(printme)


This all works fine, except my function doesn't recognize or use the if statement at all, and just prints with a precision of 6. I have never seen a parameter like this before. How can I change my function to accept it, without changing the piece of code itself?

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