[Python] Python how to set dict key as 01, 02, 03 ... when using dpath?

Let's say we want to create/maintain a dict with below key structure

{
"a": {"bb": {"01": "some value 01",
"02": "some value 02",
} },
}


We use dpath .new() as below to do this

import dpath

d=dict() ; print(d) # d={}
dpath.new(d,'a/bb/00/c', '00val') ; print(d) # d={'a': {'bb': [{'c': '00val'}]}}
# d # NOTE this will set :bb as a list, and set at bb[00] ie idx=0 of list bb
# d # what we want instead is d={'a': {'bb': {'00': {'c': '00val'} }}}
# d # what we want is NOT d={'a': {'bb': [ {'c': '00val'} ]}}


So when using 00 in the path, dpath translate it into list index at 0 instead of dict key 00

The question is how to set key as 00? Currently I have to dodge it by setting prefix s ie s00 s01 s02

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