I have an excel file with different sections, each one with its header, of which i provide its names (they also have a number attached to it on second column). On a first approach, i want to read and print on screen each section's cells. Here is the code I used: section_headers = [ 'LIBROS', 'CAPÍTULOS DE LIBROS','ARTÍCULOS CIENTÍFICOS (ORIGINALES Y DE REVISIÓN)', 'ARTÍCULOS DE DIVULGACIÓN','PONENCIAS PRESENTADAS','CARTELES PRESENTADOS EN CONGRESOS', 'CURSOS IMPARTIDOS','SEMINARIOS IMPARTIDOS','PROGRAMAS DE RADIO Y TV','PODCASTS','SOFTWARE', 'PATENTES', 'MODELOS DE UTILIDAD', 'PROTOTIPO', 'PRÁCTICAS PROFESIONALES', 'SERVICIO SOCIAL', 'TESIS','OTROS (Ej. Manuales, procesos)'] def process_excel(file_path, section_headers): df = pd.read_excel(file_path, skiprows=2) sections = {} current_section = None section_data = [] for idx, row in df.iterrows(): if any(header in str(row[0]) for header in section_headers) and isinstance(row[1], (int, float)): if current_section is not None: sections[current_section] = pd.DataFrame(section_data) current_section = row[0] # The first column is the section name section_data = [] # Reset data for the new section else: # Add row data to current section section_data.append(row) if current_section is not None: sections[current_section] = pd.DataFrame(section_data) for section, data in sections.items(): print(f"\nSection: {section}") print(data) Now, when I call the function: process_excel(file_path='wherever the file is", section_headers) i obtain nothing. I am running it on google colab. I already charged pandas and openpyxl. Any ideas on why i don't see anything (not even a error message)? Continue reading...