[Python] Python - Convert string to CamelCase

I coded the following method to convert a string to Camel Case. However, it doesn't work when the string starts with a space.

def CamelCase(s):

newString = ''
newString += s[0].upper()

for k in range(1, len(s)):
if s[k] == ' ':
newString += s[k + 1].upper()
k += 1
elif s[k - 1] != ' ':
newString += s[k]
return newString


The input is: " I love chocolate." And the output should be: "ILoveChocolate."

But it gives the following error:

IndexError Traceback (most recent call last)
<ipython-input-13-28f7ddba2ba2> in <module>
----> 1 print(CamelCase(" Algoritmos y estructuras de datos "))

<ipython-input-12-29aa8012fb61> in CamelCase(s)
9 for k in range(1, len(s)):
10 if s[k] == ' ':
---> 11 nuevaCadena += s[k + 1].upper()
12 k += 1
13 elif s[k - 1] != ' ':

IndexError: string index out of range


Help?

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