[Python] python 3 - concurrent.futures - get thread number

Currently this code prints,

MainThread done at sec 1
MainThread done at sec 1
MainThread done at sec 2
MainThread done at sec 1
MainThread done at sec 0
MainThread done at sec 3
MainThread done at sec 2
MainThread done at sec 5
MainThread done at sec 4


I need it to print

MainThread 1 done at sec 1
MainThread 3 done at sec 1
MainThread 2 done at sec 2
MainThread 3 done at sec 1
MainThread 1 done at sec 0
MainThread 2 done at sec 3
MainThread 2 done at sec 2
MainThread 3 done at sec 5
MainThread 1 done at sec 4


How can I do this, by modifying this 1 line of code.

print(threading.current_thread().name + ' done at sec ' + str(future.result()))


Here is the full code

import concurrent.futures
import threading
import pdb
import time
import random


def Threads2(time_sleep):
time.sleep(time_sleep)
return time_sleep


all_sections = [random.randint(0, 5) for iii in range(10)]

test1 = []
with concurrent.futures.ThreadPoolExecutor(max_workers=3, thread_name_prefix="Ok") as executor:
working_threads = {executor.submit(Threads2, time_sleep): time_sleep for index, time_sleep in enumerate(all_sections)}

for future in concurrent.futures.as_completed(working_threads):
print(threading.current_thread().name + ' done at sec ' + str(future.result()))

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