[Python] pymongo create a dict based on a group match

I'm new to pymongo and can't quite wrap my head around the logic of creating a nested group and match.

Im trying to find all the unique models types and then create a list of the logical names used for the models.

The output that I want to create, or close to it.

{
{"Model-1", {Devices: ["Name-1","Name-4"]},
{"Model-2", {Devices: ["Name-2","Name-3"]}
}


Mongo DB Data:

[
{
"_id": "1",
"cdate": {
"$date": "2023-11-16T00:00:00.000Z"
},
"AP Name": "Name-1",
"Model": "Model-1"
},
{
"_id": "2",
"cdate": {
"$date": "2023-11-16T00:00:00.000Z"
},
"AP Name": "Name-2",
"Model": "Model-2"
},
{
"_id": "3",
"cdate": {
"$date": "2023-11-16T00:00:00.000Z"
},
"AP Name": "Name-3",
"Model": "Model-2"
},
{
"_id": "4",
"cdate": {
"$date": "2023-11-16T00:00:00.000Z"
},
"AP Name": "Name-4",
"Model": "Model-1"
}
]


My code: I dont think this is the best way to do this.. so any help or suggestions woudld be great.

def mongo_aggregate_tags(foo_coll, foo_keyword, foo_match, x):
agg_sites = foo_coll.aggregate(
[
{"$match": {f"{foo_match}": x}},
{"$group": {"_id": f"${foo_keyword}"}},
{"$sort": {foo_keyword: 1}},
]
)
return agg_sites


for f_item in coll_inv.distinct("Model"):
for x in mongo_aggregate_tags(coll_inv, "Model", "AP Name", f_item):
print(x, " ", f_item)
print(type(x))


The output I actually get looks like this:

{'_id': 'Model-1'} Name-1
{'_id': 'Model-1'} Name-4
{'_id': 'Model-2'} Name-2
{'_id': 'Model-2'} Name-3

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