[Python] Print an error message without printing a traceback and close the program when a...

I've seen similar questions to this one, but none of them really address the traceback. If I have a class like so:

class Stop_if_no_then():
def __init__(self, value one, operator, value_two, then, line_or_label, line_number):
self._firstvalue = value_one
self._secondvalue = value_two
self._operator = operator
self._gohere = line_or_label
self._then = then
self._line_number = line_number

def execute(self, OtherClass):
"code comparing the first two values and making changes etc"


What I want my execute method to be able to do is, if self._then is not equal to the string "THEN" (in allcaps), then I want it to raise a custom error message and terminate the whole program while also not showing a traceback.

If the error is encountered, the only thing that should print out would look something like (I'm using 3 as an example, formatting is not a problem) this:

Syntax Error (Line 3): No -THEN- present in the statement.


I'm not very picky about it actually being an exception class object, so there's no issue in that aspect. Since I will be using this in a while loop, a simple if/elif just repeats the message over and over (because obviously I am not exiting the loop). I have seen sys.exit(), but that also prints out a giant block of red text, unless I am not using it correctly. I don't want to catch the exception in my loop because there are other classes in the same module in which I need to implement something like this.

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