[Python] Passing config file as argument to config parse module

My script should be called like thiks:

# python start.py --config=start.cfg


So I've got three files:

start.py

import argparse
import options

parser = argparse.ArgumentParser(prog='mystart')
parser.add_argument("-f", "--file", dest="filename",
help="write report to FILE", metavar="FILE")

args = parser.parse_args()
ConfigFile = args.filename

test = options.getTest()

print test


options.py

from ConfigReader import getConfigValue as getVal


def getTest():
Test = getVal('main', 'test')
return Test


ConfigReader.py

import os
import ConfigParser


def config():
cfg = ConfigParser.ConfigParser()
for f in ('default.cfg',):
if os.path.exists(f):
cfg.read(f)
return cfg
return None


def getConfigValue(Section, Option):
cfg = config()
if cfg.has_option(Section, Option):
return cfg.get(Section, Option)
else:
return None


As you can see my config file is hard coded in my module ConfigReader.py. How can I pass now my var ConfigFile into my module?

This is just a simple example. I have a hole bunch of files which should access this variable also.

Is a global variable an option? Is there another way?

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