A column in a pandas dataframe contains lists of values. Using a dictionary, I would like to create a new column with mapped values using the dictionary, and for any values not in the dictionary, those values are removed. Here is a minimal example: Set up of the dataframe df = pd.DataFrame(data={ 'B': ['x', 'y', 'z']}) df.at[0, 'B'] = ['jki', 'gg4', 'k6k'] df.at[1, 'B'] = ['2f4', 'gg4', 'g24'] df.at[2, 'B'] = ['1k1', 'g24', '1k1', '2f4'] Results in df B 0 [jki, gg4, k6k] 1 [2f4, gg4, g24] 2 [1k1, g24, 1k1, 2f4] Set up of the dictionary conv = { 'jki': 1, 'gg4': 2, '2f4': 3 , 'g24':4, } If the column was not a list, this code would be used df['MappedA'] = df.B.map(conv) But since the column contains lists, that code can not be used Here's what I would like the result to be B MappedA 0 [jki, gg4, k6k] [ 1 , 2 ] 1 [2f4, gg4, g24] [3, 2, 4] 2 [1k1, g24, 1k1, 2f4] [ 4 , 3 ] Continue reading...