[Python] Pagination with PyMongo and Flask

I found here a nice template for a pagination. However, this example was done with SQLlite, but I rewrote in order to be able to use PyMongo.

This script creates users and save them to MongoDB with help of PyMongo:

import sys
from pymongo import MongoClient

def fill_data(users_no):
for i in range(users_no):
doc = {
'_id': str(i),
'uname': "name_" + str(i),
}
sDB.insert(doc)


if __name__ == '__main__':
db = MongoClient().test
sDB = db.users

fill_data(1000)


I modified the orginal app.py script in onrder to be able to use PyMongo. This is the modified script:

#!/usr/bin/env python
#-*- coding: utf-8 -*-

from __future__ import unicode_literals
from flask import Flask, render_template, g, current_app, request
from flask.ext.paginate import Pagination
from pymongo import MongoClient

app = Flask(__name__)
app.config.from_pyfile('app.cfg')

@app.route('/')
def index():
db_name = "test"
col_name = "users"

db = MongoClient()
sDB = db[db_name][col_name]
total = sDB.find().count()
print total
page, per_page, offset = get_page_items()
users = sDB.find().skip(offset).limit(per_page)
for u in users:
print u
pagination = get_pagination(page=page,
per_page=per_page,
total=total,
record_name=users,
)
return render_template('index.html', users=users,
page=page,
per_page=per_page,
pagination=pagination,
)


def get_css_framework():
return current_app.config.get('CSS_FRAMEWORK', 'bootstrap3')


def get_link_size():
return current_app.config.get('LINK_SIZE', 'sm')


def show_single_page_or_not():
return current_app.config.get('SHOW_SINGLE_PAGE', False)


def get_page_items():
page = int(request.args.get('page', 1))
per_page = request.args.get('per_page')
if not per_page:
per_page = current_app.config.get('PER_PAGE', 10)
else:
per_page = int(per_page)

offset = (page - 1) * per_page
return page, per_page, offset


def get_pagination(**kwargs):
kwargs.setdefault('record_name', 'records')
return Pagination(css_framework=get_css_framework(),
link_size=get_link_size(),
show_single_page=show_single_page_or_not(),
**kwargs
)

if __name__ == '__main__':
app.run(debug=True)

• 
  Is there a way to avoid to use count() by clicking to the next or previous page in the pagination menu?
  
  
• 
  What did I forget to change so the actual user get be shown in the browser, because currently I only get the pagination menu without users?
  

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