[Python] no able to open .xlsx file using openpyxl in VS code . Gives error as shown

PS C:\Users\Asit\Desktop\python> python -u "c:\Users\Asit\Desktop\python\excel_project\excel.py"
Traceback (most recent call last):
File "c:\Users\Asit\Desktop\python\excel_project\excel.py", line 3, in <module>
wb = xl.load_workbook('transactions.xlsx')
File "C:\Users\Asit\AppData\Local\Programs\Python\Python313\Lib\site-packages\openpyxl\reader\excel.py", line 346, in load_workbook
reader = ExcelReader(filename, read_only, keep_vba,
data_only, keep_links, rich_text)
File "C:\Users\Asit\AppData\Local\Programs\Python\Python313\Lib\site-packages\openpyxl\reader\excel.py", line 123, in __init__
self.archive = _validate_archive(fn)
~~~~~~~~~~~~~~~~~^^^^
File "C:\Users\Asit\AppData\Local\Programs\Python\Python313\Lib\site-packages\openpyxl\reader\excel.py", line 95, in _validate_archive
archive = ZipFile(filename, 'r')
File "C:\Users\Asit\AppData\Local\Programs\Python\Python313\Lib\zipfile\__init__.py", line 1362, in __init__
self.fp = io.open(file, filemode)
~~~~~~~^^^^^^^^^^^^^^^^
FileNotFoundError: [Errno 2] No such file or directory: 'transactions.xlsx'


Inspite of being in the same folder its showing file not found error
I tried using absolute path and putting the in different folders. Its not working.

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