[Python] Moving elements of a python dictionary to another one under certain condition using...

OK, so this is more a code "optimization" exercise.

I have to move all elements from a python dictionary to another, under certain condition, while emptying the source dict at the same time. (No matter I find matching elements or not, the source dict must be empty by the end)

Let's have:

pie={"A1":{2000,2001,2002},"A2":{2003,2004,2005},"A3":{2000,2004,2007}} ; slices={}
condition_check=2000


As I said, I needed to move the elements to the destination dict only when they meet a certain condition. Match is made on keys and/or values while emptying the source dict, and thus I started with this code (in this case the condition is on values):

while bool(pie):
temp = pie.popitem()
if (condition_check in temp[1]): slices.update({temp[0]:temp[1]})


Now the question is: is there a way to do without the temp = pie.popitem() line? (I thought perhaps it would be possible using an assignment expression to put it within the if condition maybe?)

P.S. I know I could go with

for s in [{k:v} for k,v in pie.items() if (condition_check in v)]: slices.update(s)
pie.clear()


or, alternatively

s = {k:v for k,v in pie.items() if (condition_check in v)} ; slices.update(s)
pie.clear()


Finally, I think slices.update({k:v for k,v in pie.items() if (condition_check in v)}) ; pie.clear() could suit well

Yet I still think things might be better optimizing the first code in such a way that move the temp = pie.popitem() assignment inside the if condition somehow... And I'm just curious to know if is it possible to achieve something like that anyway tbh

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