[Python] Locals() strange behaviour python?

Why does this not work ?

Python 3.11.6 (main, Oct 8 2023, 05:06:43) [GCC 13.2.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
condition ={'RAPPORT': 1, 'COMPA': 0.815, 'varie': 'N_GRAIN'}
N_GRAIN, RAPPORT, COMPA, ACC, FREQ = 0.,0.,0.,0.,0.
print(locals()['RAPPORT'])
0.0
match = all(condition[key] == locals()[key] for key in condition if key != 'varie')

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 1, in <genexpr>
KeyError: 'RAPPORT'


I do not understand why it gives me a KeyError, as 'RAPPORT' is in condition and in locals() !?

I reproduced it on python2 but with different key error. Here is the code :

Python 2.7.18 (default, Oct 15 2023, 16:43:11)
[GCC 11.4.0] on linux2

Type "help", "copyright", "credits" or "license" for more information.
condition ={'RAPPORT': 1, 'COMPA': 0.815, 'varie': 'N_GRAIN'}
N_GRAIN, RAPPORT, COMPA, ACC, FREQ = 0.,0.,0.,0.,0.
print(locals()['RAPPORT'])
0.0
match = all(condition[key] == locals()[key] for key in condition if key != 'varie')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 1, in <genexpr>
KeyError: 'COMPA'

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