[Python] Ipv6 address format from struct.unpack

What would be the way to unpack and map to ipv6 address. I'm currently doing the following

In [3]: struct.unpack("!h",'*\x00')
Out[3]: (10752,)

In [5]: ipaddress.IPv6Address(10752)
Out[5]: IPv6Address(u'::2a00')


but of course the end result i wish for is 2a00:: , i was expecting IPv6Address to return it but i'm missing something.

What i'm currently doing is unpacking as sting then to hex and append :: .

In [14]: struct.unpack("!2s",'*\x00')
Out[14]: ('*\x00',)

In [15]: '*\x00'.encode("hex")
Out[15]: '2a00'

then append to hex and append

In [16]: '*\x00'.encode("hex")+'::'
Out[16]: '2a00::'

Continue reading...