[Python] Interaction failed when pressing button in Discord.py bot

I'm building a Discord bot using discord.py 2.5.2 that handles button interactions. When a user clicks a button, they sometimes get the "This interaction failed" message even though the bot processes the action correctly.

Here's my button click handler:

@bot.event
async def on_button_click(interaction: discord.Interaction):
try:
if str(interaction.user.id) not in ADMIN_IDS:
await interaction.response.send_message("You are not authorized to perform this action.", ephemeral=True)
return

custom_id = interaction.custom_id
message = interaction.message
embed = message.embeds[0]
user_id = embed.fields[3].value[2:-1]
amount = float(embed.fields[0].value[1:])
user = await bot.fetch_user(int(user_id))

if custom_id in ["accept_deposit", "accept_withdraw"]:
user_data = get_user_data(user_id) # Database operation
if custom_id == "accept_deposit":
user_data["balance"] += amount
await user.send(f"Your deposit of ${amount:.2f} has been approved!")
else:
user_data["balance"] -= amount
await user.send(f"Your withdrawal of ${amount:.2f} has been approved!")
save_user_data(user_id, user_data)
await message.edit(view=None)
await interaction.response.send_message("Request approved!", ephemeral=True)
else:
action = "deposit" if custom_id == "deny_deposit" else "withdrawal"
await user.send(f"Your {action} request has been denied.")
await message.edit(view=None)
await interaction.response.send_message("Request denied!", ephemeral=True)

except Exception as e:
print(f"Error in on_button_click: {e}")
if not interaction.response.is_done():
await interaction.response.send_message("An error occurred.", ephemeral=True)


The issue seems to happen because the database operations and DM sending take some time before the bot responds to the interaction. How can I properly handle the interaction to prevent the "This interaction failed" message?

Environment:

• Python 3.11
• discord.py 2.5.2
• Windows 10

`

None of these prevent the "This interaction failed" message.

1. Using interaction.response.send_message() immediately
2. Using interaction.followup.send()
3. Editing the message with view=None

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