[Python] Indexing in calling instructions. Would it be possible that a function could detect...

Having a function that returns a list:

def func1(list1):
func1_result = list1 * 2 # This is just an illustrative example to simply show that the function returns a list resulting from any function calculation.
return func1_result


And getting the whole list returned by the function with:

Example 1:

list1_1 = [5, 4, 3, 2, 1]

print(f"{func1(list1_1)}") # "[5, 4, 3, 2, 1, 5, 4, 3, 2, 1]"


Or also getting the value of a specific index of the list returned by the function, with:

Example 2:

list1_1 = [5, 4, 3, 2, 1]

print(f"{func1(list1_1)[0]}") # "5"


Then, the question is about, is there any way where the function func1 could detect if the calling instruction syntax/format is including or not the indexing part [n]? and also, when including the indexing part [n], then, how to know what specific index value is in the function calling instruction?

def func1(list1):
func1_result = []

'''
if the function calling instruction is about getting the whole resulting list:
do the function calculations to get the whole resulting list `func1_result`.
elif the function calling instruction is about getting one specific index value of the resulting list:
do the function calculations to get only the resulting value for the specified index.
# In this case the result could be a 1-element list.
# Main goal for this case: saving memory during calculations when working with large lists and with many function's calls.
'''

return func1_result


My understanding is that the indexing access specified in the calling instruction takes place after the function returns the resulting list, but maybe there would be a kind of way (ideally a direct way) which the function could get this calling format information from the calling instruction, without the need to specify it manually with an additional function parameter.

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