[Python] ignore argparse generated help and usage messages and issues errors when users give...

Let s assume I have a parser:

import argparse
def int_main():
parser = argparse.ArgumentParser(description='Process some integers.')
parser.add_argument('integers', metavar='N', type=int, nargs='+',
help='an integer for the accumulator')
parser.add_argument('--sum', dest='accumulate', action='store_const',
const=sum, default=max,
help='sum the integers (default: find the max)')

args = parser.parse_args()
print(args.accumulate(args.integers))
return 1

if __name__ == '__main__':
int_main()


Assuming the Python code above is saved into a file called prog.py. If I give it wrong arguments in the command line:

python prog.py a b c



It gives this error message:

usage: prog.py [-h] [--sum] N [N ...]
prog.py: error: argument N: invalid int value: 'a'


In a context of mine, I don't want that error message to be generated, I want for example int_main() simply to return False if any error raised indicating parsing errors.

How to do that?

I tried :

import argparse
def int_main():
parser = argparse.ArgumentParser(description='Process some integers.')
parser.add_argument('integers', metavar='N', type=int, nargs='+',
help='an integer for the accumulator')
parser.add_argument('--sum', dest='accumulate', action='store_const',
const=sum, default=max,
help='sum the integers (default: find the max)')
try:
args = parser.parse_args()
# print(args.accumulate(args.integers))
except:
return False
return True

if __name__ == '__main__':
res = int_main()
print(res)



but didn't work.

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