[Python] Identify the list that is the odd one out, and find its index from given lists

I am given a list of lists that contains exactly one list that is different from the others.

I tried to solve that with this code:

a = [[1, -2], [1, -2], [1,6], [1, -2], [1, -2]]

def find_idx(lists):
for i in range(len(lists)-1):
diff = np.array(lists[0])-np.array(lists[i+1])
for k in diff:
if k != 0:
print(i+1)
find_idx(a)


The above function works well for most inputs, but when the odd one out is at index 0, it returns the wrong result.

For example, with this input:

(lists = [[1, 6],[1, -2], [1, -2], [1, -2], [1, -2]])


I get all indices printed, except the one that I really should get (0).

How can I fix my function so it also works when the differing list sits at index 0?

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