[Python] How to show difference between two list of dictionaries

I have these two lists:

list1 = [
{'name': 'one', 'email': 'one@gmail.com', 'phone': '111'},
{'name': 'two', 'email': 'two@gmail.com', 'phone': '111'},
{'name': 'three', 'email': 'three@gmail.com', 'phone': '333'},
{'name': 'four', 'email': 'four@gmail.com', 'phone': '444'},
]
list2 = [
{'first_name': 'three', 'email': 'three@gmail.com', 'phone_number': '333'},
{'first_name': 'four', 'email': 'four@gmail.com', 'phone_number': '444'},
{'first_name': 'five', 'email': 'five@gmail.com', 'phone_number': '555'},
]


I know how to find difference between two lists based on a key:

list1_only = list(set([x['phone'] for x in list1]) - set([x['phone_number'] for x in list2]))


But the current output is:

['111']


But I'm going to have this output finally:

[
{'name': 'one', 'email': 'one@gmail.com', 'phone': '111'},
{'name': 'two', 'email': 'two@gmail.com', 'phone': '111'}
]


I know this way, but I think (and am sure) there's a better way for it:

for l in list1:
for d in diff:
if d == l['phone']:
print(l)



I read other questions like this, but it prints the whole list (not the difference values):

[x for x in list2 if x['phone_number'] not in list1]


Would you please help me regarding this?

Are there any one-line ways to replace with list1_only = list(set([x['phone'] for x in list1]) - set([x['phone_number'] for x in list2]))?

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