[Python] How to remove duplicate elements for two numpy arrays

I have two arrays named u, v, e.g.

u = np.array([1.0,2.0,2.0,3.0,4.0])
v = np.array([10.0,21.0,18.0,30.0,40.0])
a = np.array([100.0,210.0,220.0,300.0,400.0])


If two elements in u are same, then delete that one which is higher in v value. For the above example, the result should be

u_new = np.array([1.0,2.0,3.0,4.0])
v_new = np.array([10.0,18.0,30.0,40.0])
a_new = np.array([100.0,220.0,300.0,400.0])

def remove_duplicates(u,v,a):
u_new, indices = np.unique(u, return_index=True)
v_new = np.zeros(len(u_new), dtype=np.float64)
a_new = np.zeros(len(u_new), dtype=np.float64)
for i in range(len(indices)):
j1 = indices
if i < len(indices) - 1:
j2 = indices[i + 1]
else:
j2 = j1 + 1
v_new = np.amin(v[j1:j2])
k = np.argmin(v[j1:j2]) + j1
a_new = a[k]

return u_new, v_new, a_new


The above code has a problem when treat floating number because there is not exact equality between two floating number. So I have to change it to a very 'stupid' way

def remove_duplicates(u, v, a):
u_new = u
v_new = v
a_new = a
cnt = 0
for i in range(len(u)):
if cnt <1:
u_new[cnt] = u
v_new[cnt] = v
a_new[cnt] = a
cnt += 1
else:
if abs(u-u_new[cnt-1]) > 1e-5:
u_new[cnt] = u
v_new[cnt] = v
a_new[cnt] = a
cnt += 1
else:
print("Two points with same x coord found.ignore", i)
if v_new[cnt-1] > v:
v_new[cnt-1] = v
a_new[cnt-1] = a

return u_new[:cnt], v_new[:cnt], a_new[:cnt]


How can I program it in a Pythonic way?

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