[Python] how to read only last 24 hours from a multi dated log file and to grep specific...

I am reading a file from a path "F:\\RBS\\python\\Nobackupsimage.20230123"

Nobackupsimage has log file on a different days like below. I want to open the file which was created in last 24 hours and look for a specific pattern as said in the below code:

Nobackupsimage.20230123
Nobackupsimage.20230122
Nobackupsimage.20230120
Nobackupsimage.20230121


My script output:

05/01/2023 05:38:46 Unix OS backup of chsvm121626 (bkp.ind.inf.os.unv.ch4..chsvm121626.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126403 (bkp.ind.inf.os.unv.ch4..delvm126403.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126404 (bkp.ind.inf.os.unv.ch4..delvm126404.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126410 (bkp.ind.inf.os.unv.ch4..delvm126410.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126417 (bkp.ind.inf.os.unv.ch4..delvm126417.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126422 (bkp.ind.inf.os.unv.ch4..delvm126422.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126498 (bkp.ind.inf.os.unv.ch4..delvm126498.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126501 (bkp.ind.inf.os.unv.ch4..delvm126501.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126502 (bkp.ind.inf.os.unv.ch4..delvm126502.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126507 (bkp.ind.inf.os.unv.ch4..delvm126507.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126508 (bkp.ind.inf.os.unv.ch4..delvm126508.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126510 (bkp.ind.inf.os.unv.ch4..delvm126510.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126592 (bkp.ind.inf.os.unv.ch4..delvm126592.xp2) succeeded


I have 2 questions:

1. How do I look for a specific pattern and read a file that has changed in last 24 hour/8 hours ago only?

From my below output:

05/01/2023 05:38:46 Unix OS backup of delvm126417 (bkp.ind.inf.os.unv.ch4..delvm126417.xp2)
05/01/2023 05:38:46 Unix OS backup of delvm126410 (bkp.ind.inf.os.unv.ch4..delvm126410.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126417 (bkp.ind.inf.os.unv.ch4..delvm126417.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126422 (bkp.ind.inf.os.unv.ch4..delvm126422.xp2) succeeded
05/01/2023 05:38:46 Unix OS backup of delvm126498 (bkp.ind.inf.os.unv.ch4..delvm126498.xp2) succeeded

1. I want a regular expression to print the output like (server name and job name):

delvm126417 bkp.ind.inf.os.unv.ch4..delvm126417.xp2
delvm126410 bkp.ind.inf.os.unv.ch4..delvm126410.xp2
delvm126417 bkp.ind.inf.os.unv.ch4..delvm126417.xp2
delvm126422 bkp.ind.inf.os.unv.ch4..delvm126422.xp2
delvm126498 bkp.ind.inf.os.unv.ch4..delvm126498.xp2


code:

import re

errors = []
linenum = 0
pattern = re.compile("bkp.ind.inf.", re.IGNORECASE)

with open('F:\\RBS\\python\\Nobackupsimage.20230123.logtxt', 'r') as myfile:
for line in myfile:
linenum += 1
if pattern.search(line) != None:
errors.append((line.rstrip('\n')))

print("Below are the total Number of clients having issues, please check and fix:", (len(errors)))

for err in errors:
print(err)

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