[Python] How to open encrypted xlsb file?

I used this code for open encrypted .xlsx files and it's work.

path_to_my_file = r'filename.xlsx'
passwd = 'pwd'


decrypted_workbook = io.BytesIO()
with open(path_to_my_file , 'rb') as file:
office_file = msoffcryptfficeFile(file)
office_file.load_key(password=passwd)
office_file.decrypt(decrypted_workbook)


but when I use this code for read .xlsb protected file then I have error

DecryptionError Traceback (most recent call last)
Cell In[56], line 5
3 office_file = msoffcryptfficeFile(file)
4 office_file.load_key(password=passwd)
----> 5 office_file.decrypt(decrypted_workbook)

File C:\ProgramData\anaconda3\Lib\site-packages\msoffcrypto\format\ooxml.py:287, in OOXMLFile.decrypt(self, outfile, verify_integrity)
285 outfile.write(obuf)
286 elif self.type == "plain":
--> 287 raise exceptions.DecryptionError("Unencrypted document")
288 else:
289 raise exceptions.DecryptionError("Unsupported encryption method")

DecryptionError: Unencrypted document


Does anyone know the solutions to this problem?

I used this source https://pythoninoffice.com/read-encrypted-excel-file-using-pandas/

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