Context Suppose I have a model class in SQLAlchemy that looks something like this: class A(): id = Column('id', Integer, primary_key=True, autoincrement=True) title = Column('Title', String, nullable=False) type = Column('type', String) message = Column('message', String, nullable=False) If I filter this model class using query() like this: q = session.query(A) The output is the following: SELECT "A"."id" AS "A_id", "A"."title" AS "A_title", "A"."type" AS "A_type", "A"."message" AS "A_message" FROM "A" Problem I need to perform a UNION with another query that contains the same number of columns, in the same order. I need my query to be this: SELECT NULL AS "A_id", NULL AS "A_title", NULL AS "A_type", NULL AS "A_message" FROM "A" I've already tried: q = session.query(A, null()) but that just returns: SELECT "A"."id" AS "A_id", "A"."title" AS "A_title", "A"."type" AS "A_type", "A"."message" AS "A_message", NULL AS anon_1 FROM "A" Question SELECT NULL AS "A_id", NULL AS "A_title", NULL AS "A_type", NULL AS "A_message" FROM "A" How can I achieve the query shown above (inserting NULL AS as an alias)? Continue reading...