[Python] How to get link of client's request on a socket web server?

I'm trying to create a basic local web server using python sockets. You input a url into your browser (i.e. http://localhost/mysite.html), and it gives you back the requested file.

s = socket(AF_INET, SOCK_STREAM)
s.bind(('localhost', 8080))
s.listen(1)

while True:
try:
c, addr = s.accept()
# Get the url and attempt to open the file
except KeyBoardInterrupt:
break
s.close()


I can obviously receive data using c (client socket), but I don't need that, I want the link that it's requesting from the server. I have read some of socket's documentation, and cannot find anything relevant to my question.

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