[Python] How to fix the the following error 'Backend TkAgg is interactive backend. Turning...

Discussão em 'Python' iniciado por Stack, Julho 9, 2025.

  1. Stack

    Stack Membro Participativo

    I am facing an issue in the following piece of code. Basically what I am trying to do here is I am trying to check for particular phrases that are present in my data which is OCR'd from an image. I cannot share the image because of reasons. I get error "Backend TkAgg is interactive backend. Turning interactive mode on" while I try to debug the code. But I get normal exception error when run.

    imgH = imageShape[0]
    imgW = imageShape[1]
    imgWx = int(float(imgW*.5))
    wordRatio = []
    SUBJECTEXISTS = False
    dictMatch = defaultdict(str)
    try:
    for pattern in patterns:
    for word in pattern:
    if (len(word.text))>3:
    wordStripped = re.sub(r'[^\w\s]', '', word.text.lower())
    # if int(float(word.x0))<=imgWx:
    for subject in subjectList:
    if wordStripped in subject.lower():
    if Levenshtein.ratio(wordStripped,subject.lower())>.5 and wordStripped not in transcript_exclusion:
    SUBJECTEXISTS = True
    break

    except:
    for word in patterns:
    if SUBJECTEXISTS:
    break
    if (len(word.text)) > 3:
    wordStripped = re.sub(r'[^\w\s]', '', word.text.lower())
    # if int(float(word.x0))<=imgWx:
    for subject in subjectList:
    if wordStripped in subject.lower():
    if Levenshtein.ratio(wordStripped,
    subject.lower()) > .5 and wordStripped not in transcript_exclusion:
    # print("The word: ",wordStripped)
    lineValue = imageInfo[int(word.lineId)-1]
    wordsList = lineValue.text.lower().split()
    wordIdx = wordsList.index(wordStripped)
    if 'accounting' in wordStripped:
    pass
    try:
    if wordStripped in lineValue.text.lower() and 'in' in wordsList[wordIdx-1]:
    pass
    else:
    SUBJECTEXISTS = True
    break
    except:
    SUBJECTEXISTS = True
    break


    I think the error lies within the usage of break statements below SUBJECTEXISTS. Should I be concerned with this or is it just like a warning? Also I am using Pycharm IDE Does anyone have any idea what the error is?

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