[Python] How to encrypt my sentence using string libraray [closed]

My encryption/decryption program does not correctly decrypt sentences it has encrypted. As an example, when I encrypt the string I am amirreza, the encrypted output is ! Hx HxsLLxsH and the key is 13. Then, when I supply ! Hx HxsLLxsH with my key 13 to my program to be decrypted, the result is - 'm 'mz88mz', which is incorrect. I am unable to find the bug in the program.

import random
import string

while True:
print("What do you want to do? \n \t1) str to code \n \t2) code to str \n \t3) exit")
answer = input("Tell me your answer:")

if answer == "1":
sentense = input("What sentence do you want to be coded?")
list_sentense = list(sentense)
l1 = list(string.ascii_letters + string.digits + string.punctuation)
l2 = []

random.seed(len(list_sentense)) # Set seed based on sentence length

# Filling l2 with random characters
for i in range(0, len(l1)):
l2.append(random.choice(l1))

dict1 = dict(zip(l1, l2)) # Create the dictionary for encoding

# Encoding
for i in range(0, len(list_sentense)):
if list_sentense in dict1:
list_sentense = dict1[list_sentense]

encrypted_message = ''.join(list_sentense)
print("Encrypted message:", encrypted_message)
print(f"Your key to unlock the code is {len(list_sentense)}")
break

elif answer == "2":
input_coded_sentence = input("What is your coded sentence?")
key = int(input("What is your key to break the code?"))
list_input = list(input_coded_sentence)

l1 = list(string.ascii_letters + string.digits + string.punctuation)
l2 = []

random.seed(key) # Use the same seed for decoding


for i in range(0, len(l1)):
l2.append(random.choice(l1))

dict2 = dict(zip(l2, l1)) # Reverse dictionary for decoding

# Decoding
for i in range(0, len(list_input)):
if list_input in dict2: # Check if character exists in dict2
list_input = dict2[list_input]

decrypted_message = ''.join(list_input)
print("Decrypted message:", decrypted_message)
break

elif answer == "3":
print("Goodbye!")
break

else:
print("What are you doing?")

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