[Python] How to count full-word phrase occurrences in Python (with apostrophes and hyphens)

I'm trying to count how many times a full-word phrase appears in a text in Python, case-insensitively.

⚠️ The requirements are:

• Only exact phrase matches (in order, no fuzzy matching)
• A "word" may contain apostrophes (') and hyphens (-) inside it, such as "don't" or "skin-care"
• The phrase must match whole words only, not substrings inside other words

For example:

• "don't" should match "Don't be late!"
• "maley" should not match "O'maley"
• "skin-care monopoly" should match "a skin-care monopoly"
• "care" should not match "skin-care"

Here is the base function:

def count_occurrences_in_text(word, text):
"""
Count full-word phrase occurrences in the text, case-insensitive.
Words may contain apostrophes and hyphens inside words (like don't, skin-care),
but matches must be exact and not part of larger words.
"""
# TODO: Implement robust logic
pass


assert count_occurrences_in_text("don't", "Don't be late!") == 1
assert count_occurrences_in_text("maley", "John O'maley is my friend") == 0
assert count_occurrences_in_text("skin-care", "Enable a skin-care monopoly") == 1
assert count_occurrences_in_text("care", "Enable a skin-care monopoly") == 0
assert count_occurrences_in_text("Linguist", "'''Linguist Specialist Found Dead on Floor'''") == 1
assert count_occurrences_in_text("reflexion mirror", 'I live at the “Reflexion Mirror” resort') == 1
assert count_occurrences_in_text("reflexion mirror", '...Fun-Plex «Reflexion Mirror»...') == 1
assert count_occurrences_in_text("legitimate their", "This is legitimate: their employees...") == 0
assert count_occurrences_in_text("get back to me", "When you know: get back to me.") == 1





I try a lot of things but nothing conclusive.

`text.lower().count(word.lower())`
Using regex with \b

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