[Python] How to capture all values in a regex while matching a specific pattern? [duplicate]

Problem


I would like to match strings following this pattern:

prefix (value 0) (value 1) (value 2)


with one or more text values, and get a list of all values. (here: ['value 0', 'value 1', 'value 2'])

Possible solution


One way to do this, using re:

import re

text = ... # some string

if re.match(r"prefix (\([\w ]*\))+", text):
values = re.findall(r"\(([\w ]*)\)", text)
print(len(values), "values found:")
for value in values:
print('-', value)
else:
print("No match for:", text)

Question


My approach looks greedy, since it has to match the string twice. Is there a more elegant way to do this? I'm not sure if re is the right tool for that actually.

Note that I am not looking for a repeated capture of a pattern with re.match (I know that there is none).

Continue reading...